Tomb of Ramesses IV The pharaoh Ramesses IV was buried in Tomb KV2, located in the Valley of the Kings, Egypt. The tombs of Ramesses II and VII are on either side. Ramesses died at the age of 27 in 1148 BC. He is connected to the Temple of Khonsu at Karnak. Coordinates 25.741530,32.602080 Description The tomb is of similar design to others in that it has a corridor to the burial chamber with side rooms. It is thought to be about 75 metres long and declines about 10 metres from the entrance. Chamber E, as the antechamber, has stars painted on the ceiling. Chamber K is built with side rooms, and the burial chamber J has a vaulted ceiling with astrological patterns along with the sarcophagus. Coptic monks were said to have lived in the tomb, and in the 19th century, explorers like Jean-François Champollion had camped there. Earlier, Romans were said to have left what is considered as graffiti in the tomb. Measurements Entrance A 14.01m by 3.66m (51.2766) Corridor B 15.17m by 3....
Possible Neolithic Stone Circle
In Neolithic times, it was normal to erect various stones, which would have meanings for altitude, location, or points of interest. As it approached towards the Bronze Age, a common building structure would be that of a circle. These would have astrological, astronomical, and mathematical connections.
Because of the size and weight of these structures, they would require a large group of people who wanted to spend time erecting them. These circles and structures were rarely copied, with each having a different meaning, although with a common theme, they could include similar numbers but positioned differently.
Along these lines, a possible Neolithic structure could appear as the following.
The measurements are connected to gravity, obliquity, escape velocity, and 10.
The 10 gives a multiplcation of that factor with the other numbers measured in metres and scaled appropriately.
9.81 m/s gravity
11426 m/s escape velocity
These measurements are then included in the monument via a triangle. For example, escape velocity at 11.4kms is divided by 1000 to give an angle of 11.42° with a side length 10m at 90°. The opposite side would be 2.02m.
The other side would be 9.81m long ending in an angle of 8.656° in a triangle of 90° would give a side of 1.22m.
Escape velocity 11.4kms
=11426.3424m/s
11426.3424÷1000
= 11.42° at 10m = 2.02m
Because 1.22 is very near to obliquity, then obliquity is included and gives an angle of 8.656° from the number of years from peak obliquity. Obliquity is equal to 0.0001170731°.
Peak obliquity 6642 bc
= 8.656° at 9.81m = 1.22m
6642+1985=8672 (1623 until mid point)
(8656 for 1969)
Because a scaling factor is required, this can be from a ring of stones around the outside. These would align from an angle of 25° (at maximum tilt) with a, 1 stone = 0 and 2 stones = 1.
1000 =11111000
and
³√1000
=10
The angle of 25° is used as 385000kms is the distance to the moon, which is divided by 1000 equalling 385 and 25° is 385-360°. This number would also go into height and possibly average width of radius from main stone.
This would make it 7.62m high and 15.24m wide.
The volume and weight of an object this size would be.
16 sqm² base
16×7.62 height
121.93 cubic m³
121.93×2.5=305 metric tons
A weight of 2.5 tonnes/m³ is for the average weight of sandstone with all measurements in metres.
As a comparison, the capstone on Gravinis is about 120 metric tons at 11m long (6:1 ratio).
Archeology77 ©
In Neolithic times, it was normal to erect various stones, which would have meanings for altitude, location, or points of interest. As it approached towards the Bronze Age, a common building structure would be that of a circle. These would have astrological, astronomical, and mathematical connections.
Because of the size and weight of these structures, they would require a large group of people who wanted to spend time erecting them. These circles and structures were rarely copied, with each having a different meaning, although with a common theme, they could include similar numbers but positioned differently.
Along these lines, a possible Neolithic structure could appear as the following.
The measurements are connected to gravity, obliquity, escape velocity, and 10.
The 10 gives a multiplcation of that factor with the other numbers measured in metres and scaled appropriately.
9.81 m/s gravity
11426 m/s escape velocity
These measurements are then included in the monument via a triangle. For example, escape velocity at 11.4kms is divided by 1000 to give an angle of 11.42° with a side length 10m at 90°. The opposite side would be 2.02m.
The other side would be 9.81m long ending in an angle of 8.656° in a triangle of 90° would give a side of 1.22m.
Escape velocity 11.4kms
=11426.3424m/s
11426.3424÷1000
= 11.42° at 10m = 2.02m
Because 1.22 is very near to obliquity, then obliquity is included and gives an angle of 8.656° from the number of years from peak obliquity. Obliquity is equal to 0.0001170731°.
Peak obliquity 6642 bc
= 8.656° at 9.81m = 1.22m
6642+1985=8672 (1623 until mid point)
(8656 for 1969)
Because a scaling factor is required, this can be from a ring of stones around the outside. These would align from an angle of 25° (at maximum tilt) with a, 1 stone = 0 and 2 stones = 1.
1000 =11111000
and
³√1000
=10
The angle of 25° is used as 385000kms is the distance to the moon, which is divided by 1000 equalling 385 and 25° is 385-360°. This number would also go into height and possibly average width of radius from main stone.
This would make it 7.62m high and 15.24m wide.
The volume and weight of an object this size would be.
16 sqm² base
16×7.62 height
121.93 cubic m³
121.93×2.5=305 metric tons
A weight of 2.5 tonnes/m³ is for the average weight of sandstone with all measurements in metres.
As a comparison, the capstone on Gravinis is about 120 metric tons at 11m long (6:1 ratio).
Archeology77 ©
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